Test Preparation Solved MCQs Notes With Their Correct Answer.
If you are searching for the solved important MCQs of 11th class Physics then here we have shared the 1st Year Physics Chapter-wise MCQs pdf Download or you can read them online.
1. The SI standard of time is based on:
A. the daily rotation of the earth
B. the frequency of light emitted by Kr86
C. the yearly revolution of the earth about the sun
D. none of these
2. A nanosecond is:
A. 109 s
B. 10−9 s
C. 10−10 s
D. 10−10 s
3. The SI standard of length is based on:
A. the distance from the north pole to the equator along a meridian passing through Paris
B. wavelength of light emitted by Hg198
C. wavelength of light emitted by Kr86
D. the speed of light
4. In 1866, the U. S. Congress defined the U. S. yard as exactly 3600/3937 international meter.
This was done primarily because:
A. length can be measured more accurately in meters than in yards
B. the meter is more stable than the yard
C. this definition relates the common U. S. length units to a more widely used system
D. there are more wavelengths in a yard than in a meter
5. Which of the following is closest to a yard in length?
A. 0.01 m
B. 0.1 m
C. 1 m
D. 100 m
6. There is no SI base unit for the area because:
A. an area has no thickness; hence no physical standard can be built
B. we live in a three (not a two) dimensional world
C. it is impossible to express square feet in terms of meters
D. area can be expressed in terms of square meters
7. The SI base unit for mass is:
A. gram
B. pound
C. kilogram
D. ounce
8. A gram is:
A. 10−6 kg
B. 10−3 kg
C. 1 kg
D. 103 kg
9. Which of the following weighs about a pound?
A. 0.05 kg
B. 0.5 kg
C. 5 kg
D. 50 kg
10. (5.0 × 104) × (3.0 × 106) =
A. 1.5 × 109
B. 1.5 × 1010
C. 1.5 × 1011
D. 1.5 × 1012
11. (5.0 × 104) × (3.0 × 10−6) =
A. 1.5 × 10−3
B. 1.5 × 10−1
C. 1.5 × 101
D. 1.5 × 103
12. 5.0 × 105 + 3.0 × 106 =
A. 8.0 × 105
B. 8.0 × 106
C. 5.3 × 105
D. 3.5 × 106
13. (7.0 × 106)/(2.0 × 10−6) =
A. 3.5 × 10−12
B. 3.5 × 10−6
C. 3.5
D. 3.5 × 1012
14. The number of significant figures in 0.00150 is:
A. 2
B. 3
C. 4
D. 5
15. The number of significant figures in 15.0 is:
A. 1
B. 2
C. 3
D. 4
16. 3.2 × 2.7 =
A. 9
B. 8
C. 8.6
D. 8.64
17. 1.513 + 27.3 =
A. 29
B. 28.8
C. 28.9
D. 28.81
18. 1 mi is equivalent to 1609 m so 55 mph is:
A. 15 m/s
B. 25 m/s
C. 66 m/s
D. 88 m/s
19. A sphere with a radius of 1.7 cm has a volume of:
A. 2.1 × 10−5 m3
B. 9.1 × 10−4 m3
C. 3.6 × 10−3 m3
D. 0.11 m3
20. A sphere with a radius of 1.7 cm has a surface area of:
A. 2.1 × 10−5 m2
B. 9.1 × 10−4 m2
C. 3.6 × 10−3 m2
D. 0.11 m2
21. A right circular cylinder with a radius of 2.3 cm and a height of 1.4 m has a volume of:
A. 0.20 m3
B. 0.14 m3
C. 9.3 × 10−3 m3
D. 2.3 × 10−3 m3
22. A right circular cylinder with a radius of 2.3 cm and a height of 1.4 cm has a total surface area
of:
A. 1.7 × 10−3 m2
B. 3.2 × 10−3 m2
C. 2.0 × 10−3 m3
D. 5.3 × 10−3 m2
23. A cubic box with an edge of exactly 1 cm has a volume of:
A. 10−9 m3
B. 10−6 m3
C. 10−3 m3
D. 103 m3
E. 106 m3
24. A square with an edge of exactly 1 cm has an area of:
A. 10−6 m2
B. 10−4 m2
C. 102 m2
D. 104 m2
E. 106 m2
25. 1 m is equivalent to 3.281 ft. A cube with an edge of 1.5 ft has a volume of:
A. 1.2 × 102 m3
B. 9.6 × 10−2 m3
C. 10.5 m3
D. 9.5 × 10−2 m3
26. During a short interval of time, the speed v in m/s of an automobile is given by v = at2 + bt3,
where the time t is in seconds. The units of a and b are respectively:
A. m · s2; m · s4
B. s3/m; s4/m
C. m/s2; m/s3
D. m/s3; m/s4E. m/s 4; m/s5
27. Suppose A = BC, where A has the dimension L/M and C has the dimension L/T. Then B
has the dimension:
A. T/M
B. L2/TM
C. TM/L2
D. L2T/M
USAT MDCAT PHYSICS PAST PAPER SOLVED MCQS